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2020年山東新高考全國1卷化學(xué)試題及答案

2020-07-11 15:59:59文/鐘詩賀

以下試題真題如有排版問題請點(diǎn)擊文末下載查看

 

山東省2020年普通高中學(xué)業(yè)水平等級(jí)考

化? 學(xué)

注意事項(xiàng):

1.答卷前,考生務(wù)必將自己的姓名、考生號(hào)等填寫在答題卡和試卷指定位置。

2.回答選擇題時(shí),選出每小題答案后,用鉛筆把答題卡上對(duì)應(yīng)題目的答案標(biāo)號(hào)涂黑。如需改動(dòng),用橡皮擦干凈后,再選涂其他答案標(biāo)號(hào)?;卮鸱沁x擇題時(shí),將答案寫在答題卡上。寫在本試卷上無效。

3.考試結(jié)束后,將本試卷和答題卡一并交回。

可能用到的相對(duì)原子質(zhì)量:H 1? C 12? O 16? Na 23? Cl 35.5? Fe 56

一、選擇題:本題共10小題,每小題2分,共20分。每小題只有一個(gè)選項(xiàng)符合題目要求。

1.實(shí)驗(yàn)室中下列做法錯(cuò)誤的是

A.用冷水貯存白磷?? ????????????? ??????? ????????????? ????????????? ????????????? B.用濃硫酸干燥二氧化硫

C.用酒精燈直接加熱蒸發(fā)皿???????? ????????????? ????????????? D.用二氧化碳滅火器撲滅金屬鉀的燃燒

2.下列敘述不涉及氧化還原反應(yīng)的是

A.谷物發(fā)酵釀造食醋???????????? ????????????? ????????????? ????????????? B.小蘇打用作食品膨松劑

C.含氯消毒劑用于環(huán)境消毒??????? ????????????? ????????????? D.大氣中NO2參與酸雨形成

3.短周期主族元素X、Y、Z、W的原子序數(shù)依次增大,基態(tài)X原子的電子總數(shù)是其最高能級(jí)電子數(shù)的2倍,Z可與X形成淡黃色化合物Z2X2,Y、W最外層電子數(shù)相同。下列說法正確的是

A.第一電離能:W>X>Y>Z??????? ????????????? ????????????? ????????????? B.簡單離子的還原性:Y>X>W

C.簡單離子的半徑:W>X>Y>Z???? ????????????? ????????????? D.氫化物水溶液的酸性:Y>W

4.下列關(guān)于C、Si及其化合物結(jié)構(gòu)與性質(zhì)的論述錯(cuò)誤的是

A.鍵能eqWmf183GmgAAAAAAAOAIwAEBCQAAAAAwVwEACQAAA6gBAAACAKMAAAAAAAUAAAACAQEAAAAFAAAAAQL/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、eqWmf183GmgAAAAAAAMAIwAEBCQAAAAAQVwEACQAAA6QBAAACAKAAAAAAAAUAAAACAQEAAAAFAAAAAQL/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,因此C2H6穩(wěn)定性大于Si2H6

B.立方型SiC是與金剛石成鍵、結(jié)構(gòu)均相似的共價(jià)晶體,因此具有很高的硬度

C.SiH4中Si的化合價(jià)為+4,CH4中C的化合價(jià)為-4,因此SiH4還原性小于CH4

D.Si原子間難形成雙鍵而C原子間可以,是因?yàn)镾i的原子半徑大于C,難形成eqWmf183GmgAAAAAAAIAEoAEBCQAAAAAwWwEACQAAA58BAAACAJcAAAAAAAUAAAACAQEAAAAFAAAAAQL/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5.利用下列裝置(夾持裝置略)進(jìn)行實(shí)驗(yàn),能達(dá)到實(shí)驗(yàn)?zāi)康牡氖?/p>

A.用甲裝置制備并收集CO2

B.用乙裝置制備溴苯并驗(yàn)證有HBr產(chǎn)生

C.用丙裝置制備無水MgCl2

D.用丁裝置在鐵上鍍銅

6.從中草藥中提取的 calebin A(結(jié)構(gòu)簡式如下)可用于治療阿爾茨海默癥。下列關(guān)于 calebin A的說法錯(cuò)誤的是

A.可與FeCl3溶液發(fā)生顯色反應(yīng)

B.其酸性水解的產(chǎn)物均可與Na2CO3溶液反應(yīng)

C.苯環(huán)上氫原子發(fā)生氯代時(shí),一氯代物有6種

D.1mol該分子最多與8molH2發(fā)生加成反應(yīng)

7.B3N3H6(無機(jī)苯)的結(jié)構(gòu)與苯類似,也有大π鍵。下列關(guān)于B3N3H6的說法錯(cuò)誤的是

A.其熔點(diǎn)主要取決于所含化學(xué)鍵的鍵能

B.形成大π鍵的電子全部由N提供

C.分子中B和N的雜化方式相同

D.分子中所有原子共平面

8.實(shí)驗(yàn)室分離Fe3+和Al3+的流程如下:

已知Fe3+在濃鹽酸中生成黃色配離子[FeCl4]-,該配離子在乙醚(Et2O,沸點(diǎn)34.6℃)中生成締合物eqWmf183GmgAAAAAAAIANYAIACQAAAADxUQEACQAAA1QCAAACANoAAAAAAAUAAAACAQEAAAAFAAAAAQL/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 。下列說法錯(cuò)誤的是

A.萃取振蕩時(shí),分液漏斗下口應(yīng)傾斜向下

B.分液時(shí),應(yīng)先將下層液體由分液漏斗下口放出

C.分液后水相為無色,說明已達(dá)到分離目的

D.蒸餾時(shí)選用直形冷凝管

9.以菱鎂礦(主要成分為MgCO3,含少量SiO2/Fe2O3和Al2O3)為原料制備高純鎂砂的工藝流程如下:

已知浸出時(shí)產(chǎn)生的廢渣中有SO2、Fe(OH)3和Al(OH)3。下列說法錯(cuò)誤的是

A.浸出鎂的反應(yīng)為

B.浸出和沉鎂的操作均應(yīng)在較高溫度下進(jìn)行

C.流程中可循環(huán)使用的物質(zhì)有NH3、NH4Cl

D.分離Mg2+與Al3+、Fe3+是利用了它們氫氧化物Ksp的不同

10.微生物脫鹽電池是一種高效、經(jīng)濟(jì)的能源裝置,利用微生物處理有機(jī)廢水獲得電能,同時(shí)可實(shí)現(xiàn)海水淡化?,F(xiàn)以NaCl溶液模擬海水,采用惰性電極,用下圖裝置處理有機(jī)廢水(以含 CH3COO-的溶液為例)。下列說法錯(cuò)誤的是

A.負(fù)極反應(yīng)為

B.隔膜1為陽離子交換膜,隔膜2為陰離子交換膜

C.當(dāng)電路中轉(zhuǎn)移1mol電子時(shí),模擬海水理論上除鹽58.5g

D.電池工作一段時(shí)間后,正、負(fù)極產(chǎn)生氣體的物質(zhì)的量之比為2:1

二、選擇題:本題共5小題,每小題4分,共20分。每小題有一個(gè)或兩個(gè)選項(xiàng)符合題目要求,全部選對(duì)得4分,選對(duì)但不全的得2分,有選錯(cuò)的得0分。

11.下列操作不能達(dá)到實(shí)驗(yàn)?zāi)康牡氖?/p>

 

目的

操作

A

除去苯中少量的苯酚

加入適量NaOH溶液,振蕩、靜置、分液

B

證明酸性:碳酸>苯酚

將鹽酸與NaHCO3混合產(chǎn)生的氣體直接通入苯酚鈉溶液

C

除去堿式滴定管膠管內(nèi)的氣泡

將尖嘴垂直向下,擠壓膠管內(nèi)玻璃球?qū)馀菖懦?/p>

D

配制用于檢驗(yàn)醛基的氫氧化銅懸濁液

向試管中加入2mL10%NaOH溶液,再滴加數(shù)滴2%CuSO4溶液,振蕩

12.α-氰基丙烯酸異丁酯可用作醫(yī)用膠,其結(jié)構(gòu)簡式如下。下列關(guān)于α-氰基丙烯酸異丁酯的說法錯(cuò)誤的是

A.其分子式為 C8H11NO2

B.分子中的碳原子有3種雜化方式

C.分子中可能共平面的碳原子最多為6個(gè)

D.其任一含苯環(huán)的同分異構(gòu)體中至少有4種不同化學(xué)環(huán)境的氫原子

13.采用惰性電極,以去離子水和氧氣為原料通過電解法制備雙氧水的裝置如下圖所示。忽略溫度變化的影響,下列說法錯(cuò)誤的是

A.陽極反應(yīng)為

B.電解一段時(shí)間后,陽極室的pH未變

C.電解過程中,H+由a極區(qū)向b極區(qū)遷移

D.電解一段時(shí)間后,a極生成的O2與b極反應(yīng)的O2等量

14.1,3-丁二烯與HBr發(fā)生加成反應(yīng)分兩步:第一步H+進(jìn)攻1,3-丁二烯生成碳正離子();第二步Br -進(jìn)攻碳正離子完成1,2-加成或1,4-加成。反應(yīng)進(jìn)程中的能量變化如下圖所示。已知在0℃和40℃時(shí),1,2-加成產(chǎn)物與1,4-加成產(chǎn)物的比例分別為70:30和15:85。下列說法正確的是

A.1,4-加成產(chǎn)物比1,2-加成產(chǎn)物穩(wěn)定

B.與0℃相比,40℃時(shí)1,3-丁二烯的轉(zhuǎn)化率增大

C.從0℃升至40℃,1,2-加成正反應(yīng)速率增大,1,4-加成正反應(yīng)速率減小

D.從0℃升至40℃,1,2-加成正反應(yīng)速率的增大程度小于其逆反應(yīng)速率的增大程度

15.25℃時(shí),某混合溶液中eqWmf183GmgAAAAAAAGAagAIACQAAAADxRgEACQAAA9IDAAACAE8BAAAAAAUAAAACAQEAAAAFAAAAAQL/
//8ABQAAAC4BGQAAAAUAAAALAgAAAAAFAAAADAKAAmAaCwAAACYGDwAMAE1hdGhUeXBlAABwABIA
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DAEAAQABAgICAgACAAEBAQADAAEABAAFAAoBABAAAAAAAAAADwECAINjAAMAAQMADwABAA8BAgCB
QwACAIFIAA8AAwAbAAALAQAPAQIAiDMAAA8AAQEACg8BAgCBQwACAIFPAAIAgU8AAgCBSAAAAgCW
KAACAJYpAAACBIYrACsCAINjAAMAAQMADwABAA8BAgCBQwACAIFIAA8AAwAbAAALAQAPAQIAiDMA
AA8AAQEACg8BAgCBQwACAIFPAAIAgU8AAAIAligAAgCWKQAAAgSGPQA9AgCIMAACAIIuAAIAiDEA
AgCBbQACAIFvAAIAgWwAAgSGxSLXAgCBTAAPAAMAHAAACwEBAQAPAQIEhhIiLQIAiDEAAAAAAAAK
AAAAJgYPAAoA/////wEAAAAAABwAAAD7AhAABwAAAAAAvAIAAACGAQICIlN5c3RlbQBb3hdmWwAA
CgA4AIoBAAAAAAAAAAAU4hgABAAAAC0BAAAEAAAA8AEBAAMAAAAAAA==,1gc( CH3COOH)、1gc(CH3COO-)、lgc(H+)和lgc(OH-)隨pH變化的關(guān)系如下圖所示。Ka為CH3COOH的電離常數(shù),下列說法正確的是

A.O點(diǎn)時(shí),

B.N點(diǎn)時(shí),

C.該體系中,

D.pH由7到14的變化過程中, CH3COO-的水解程度始終增大

三、非選擇題:本題共5小題,共60分

16.(12分)用軟錳礦(主要成分為MnO2,含少量Fe3O4、Al2O3)和BaS制備高純MnCO3的工藝流程如下:

已知:MnO2是一種兩性氧化物;25℃時(shí)相關(guān)物質(zhì)的Ksp見下表。

物質(zhì)

Fe(OH)2

Fe(OH)3

Al(OH)3

Mn(OH)2

Ksp

回答下列問題:

(1)軟錳礦預(yù)先粉碎的目的是??????????? ,MnO2與BaS溶液反應(yīng)轉(zhuǎn)化為MnO的化學(xué)方程式為??????? 。

(2)保持BaS投料量不變,隨MnO2與BaS投料比增大,S的量達(dá)到最大值后無明顯變化,而Ba(OH)2的量達(dá)到最大值后會(huì)減小,減小的原因是??????? 。

(3)濾液I可循環(huán)使用,應(yīng)當(dāng)將其導(dǎo)入到??????? 操作中(填操作單元的名稱)。

(4)凈化時(shí)需先加入的試劑X為??????? (填化學(xué)式)。再使用氨水調(diào)溶液的pH,則pH的理論最小值為_______(當(dāng)溶液中某離子濃度時(shí),可認(rèn)為該離子沉淀完全)。

(5)碳化過程中發(fā)生反應(yīng)的離子方程式為????????????????????? 。

17.(12分)CdSnAs2是一種高遷移率的新型熱電材料,回答下列問題:

(1)Sn為ⅣA族元素,單質(zhì)Sn與干燥Cl2反應(yīng)生成SnCl4。常溫常壓下SnCl4為無色液體,SnCl4空間構(gòu)型為???????????? ,其固體的晶體類型為???????????? 。

(2)NH3、PH3、AsH3的沸點(diǎn)由高到低的順序?yàn)???????????? (填化學(xué)式,下同),還原性由強(qiáng)到弱的順序?yàn)??????????? ,鍵角由大到小的順序?yàn)???????????? 。

(3)含有多個(gè)配位原子的配體與同一中心離子(或原子)通過螯合配位成環(huán)而形成的配合物為螯合物。一種Cd2+配合物的結(jié)構(gòu)如圖所示, 1mol該配合物中通過螯合作用形成的配位鍵有???????? mol,該螯合物中N的雜化方式有????????? 種。

(4)以晶胞參數(shù)為單位長度建立的坐標(biāo)系可以表示晶胞中各原子的位置,稱作原子的分?jǐn)?shù)坐標(biāo)。四方晶系CdSnAs2的晶胞結(jié)構(gòu)如下圖所示,晶胞棱邊夾角均為90°,晶胞中部分原子的分?jǐn)?shù)坐標(biāo)如下表所示。

坐標(biāo)

原子

x

y

z

Cd

0

0

0

Sn

0

0

0.5

As

0.25

0.25

0.125

一個(gè)晶胞中有???????? 個(gè)Sn,找出距離Cd(0,0,0)最近的Sn???????? (用分?jǐn)?shù)坐標(biāo)表示)。CdSnAs2晶體中與單個(gè)Sn鍵合的As有?????????? 個(gè)。

18.(12分)探究CH3OH合成反應(yīng)化學(xué)平衡的影響因素,有利于提高CH3OH的產(chǎn)率。以CO2、H2為原料合成CH3OH涉及的主要反應(yīng)如下:

Ⅰ. ????????????? ????????????? ?????????????

Ⅱ. ????????????? ????????????? ????????????? ????????????? ?????????????

Ⅲ. eqWmf183GmgAAAAAAAEAVQAIACQAAAAARSQEACQAAA1gCAAACADABAAAAAAUAAAACAQEAAAAFAAAAAQL/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e0h9X3syfSBcbWF0aHJte099KFxtYXRocm17Z30pABNXaW5BbGxCYXNpY0NvZGVQYWdlcwARBVRp
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APIfIKXyCiX0jyH0EA9BAPQPSPQX9I9BAPIaX0RfRfRfRfRfQQ8MAQABAAECAgICAAIAAQEBAAMA
AQAEAAUACgEAEAAAAAAAAAAPAQIAgUMAAgCBTwAPAAMAGwAACwEADwECAIgyAAAPAAEBAAoPAQIA
gigAAgCBZwACAIIpAAIEhisAKwIAgUgADwADABsAAAsBAA8BAgCIMgAADwABAQAKDwECAIIoAAIA
gWcAAgCCKQACBIY9AD0CAIFDAAIAgU8AAgCCKAACAIFnAAIAgikAAgSGKwArAgCBSAAPAAMAGwAA
CwEADwECAIgyAAAPAAEBAAoPAQIAgU8AAgCCKAACAIFnAAIAgikAAAAKAAAAJgYPAAoA/////wEA
AAAAABwAAAD7AhAABwAAAAAAvAIAAACGAQICIlN5c3RlbQBSexdmUgAACgA4AIoBAAAAAAEAAAAU
4hgABAAAAC0BAQAEAAAA8AEAAAMAAAAAAA==????????????? ????????????? ????????????? ?????????????

回答下列問題:

(1)eqWmf183GmgAAAAAAAAALYAIACQAAAABxVwEACQAAA5QCAAACAO4AAAAAAAUAAAACAQEAAAAFAAAAAQL/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(2)一定條件下,向體積為VL的恒容密閉容器中通入1 mol CO2和3 mol H2發(fā)生上述反應(yīng),達(dá)到平衡時(shí),容器中CH3OH(g)為ɑ mol,CO為b mol,此時(shí)H2O(g)的濃度為????????? mol﹒L-1(用含a、b、V的代數(shù)式表示,下同),反應(yīng)Ⅲ的平衡常數(shù)為?????????? 。

(3)不同壓強(qiáng)下,按照n(CO2):n(H2)=1:3投料,實(shí)驗(yàn)測定CO2的平衡轉(zhuǎn)化率和CH3OH的平衡產(chǎn)率隨溫度的變化關(guān)系如下圖所示。

已知:CO2的平衡轉(zhuǎn)化率=

CH3OH的平衡產(chǎn)率=eqWmf183GmgAAAAAAAOARoAQACQAAAABRSwEACQAAA7YFAAAEAE8BAAAAAAUAAAACAQEAAAAFAAAAAQL/
//8ABQAAAC4BGQAAAAUAAAALAgAAAAAFAAAADAKgBOARCwAAACYGDwAMAE1hdGhUeXBlAAAAARIA
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APsCBf7jAAAAAACQAQAAAAEAAgAQU3ltYm9sAHXgFAqqODV/ABTbGADYlFt1gAFfda8cZjIEAAAA
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ABTbGADYlFt1gAFfda8cZjIEAAAALQEAAAQAAADwAQEACQAAADIKAAAAAAEAAAAoeQAABQAAABQC
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AADwAQEADQAAADIKAAAAAAQAAAAxMDAlwADAAMAAAAMFAAAAFALMA8cDHAAAAPsCgP4AAAAAAACQ
AQAAAAAAAgAQVGltZXMgTmV3IFJvbWFuAODXGADYlFt1gAFfda8cZjIEAAAALQEBAAQAAADwAQIA
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AAAAAAAAAAAAAAQAAAAtAQIAHAAAAPsCEAAHAAAAAAC8AgAAAIYBAgIiU3lzdGVtAACvHGYyAAAK
ADgAigEAAAAA/////xTiGAAEAAAALQEDAAQAAADwAQEAAwAAAAAA

其中縱坐標(biāo)表示CO2平衡轉(zhuǎn)化率的是圖?????????? (填“甲”或“乙”);壓強(qiáng)p1、p2、p3由大到小的順序?yàn)?????????? ;圖乙中T1溫度時(shí),三條曲線幾乎交于一點(diǎn)的原因是?????????? 。

(4)為同時(shí)提高CO2的平衡轉(zhuǎn)化率和CH3OH的平衡產(chǎn)率,應(yīng)選擇的反應(yīng)條件為???????? (填標(biāo)號(hào))。

A.低溫、高壓??? B.高溫、低壓?? C.低溫、低壓? D.高溫、高壓

19.(12分)化合物F是合成吲哚-2-酮類藥物的一種中間體,其合成路線如下:

知:Ⅰ.

Ⅱ.

Ⅲ.

Ar為芳基;X=Cl,Br;Z或Z′=COR, CONHR,COOR等。

回答下列問題:

(1)實(shí)驗(yàn)室制備A的化學(xué)方程式為?????????? ,提高A產(chǎn)率的方法是????????????? ;A的某同分異構(gòu)體只有一種化學(xué)環(huán)境的碳原子,其結(jié)構(gòu)簡式為?????????????? 。

(2)C→D的反應(yīng)類型為??????????? ;E中含氧官能團(tuán)的名稱為??????????? 。

(3)C的結(jié)構(gòu)簡式為??????????? ,F(xiàn)的結(jié)構(gòu)簡式為??????????? 。

(4)Br2和的反應(yīng)與Br2和苯酚的反應(yīng)類似,以為原料合成,寫出能獲得更多目標(biāo)產(chǎn)物的較優(yōu)合成路線(其它試劑任選)。

20.(12分)某同學(xué)利用Cl2氧化K2MnO4制備KMnO4的裝置如下圖所示(夾持裝置略):

已知:錳酸鉀(K2MnO4)在濃強(qiáng)堿溶液中可穩(wěn)定存在,堿性減弱時(shí)易發(fā)生反應(yīng):

回答下列問題:

(1)裝置A中a的作用是????????????? ;裝置C中的試劑為??????????????? ;裝置A中制備Cl2的化學(xué)方程式為????????????? 。

(2)上述裝置存在一處缺陷,會(huì)導(dǎo)致KMnO4產(chǎn)率降低,改進(jìn)的方法是??????????????? 。

(3)KMnO4常作氧化還原滴定的氧化劑,滴定時(shí)應(yīng)將KMnO4溶液加入?????????? (填“酸式”或“堿式”)滴定管中;在規(guī)格為50.00mL的滴定管中,若KMnO4溶液起始讀數(shù)為15.00mL,此時(shí)滴定管中KMnO4溶液的實(shí)際體積為????????????? (填標(biāo)號(hào))。

A.15.00 mL???? B.35.00mL???? C.大于35.00mL??? D.小于15.00mL

(4)某FeC2O4·2H2O樣品中可能含有的雜質(zhì)為Fe2(C2O4)3、H2C2O4·2H2O,采用KMnO4滴定法測定該樣品的組成,實(shí)驗(yàn)步驟如下:

Ⅰ.取m g樣品于錐形瓶中,加入稀H2SO4溶解,水浴加熱至75℃。用 c mol﹒L-1的KMnO4溶液趁熱滴定至溶液出現(xiàn)粉紅色且30s內(nèi)不褪色,消耗KMnO4溶液V1mL。

Ⅱ.向上述溶液中加入適量還原劑將Fe3+完全還原為Fe2+,加入稀H2SO4酸化后,在75℃繼續(xù)用KMnO4溶液滴定至溶液出現(xiàn)粉紅色且30s內(nèi)不褪色,又消耗KMnO4溶液V2mL。

樣品中所含的質(zhì)量分?jǐn)?shù)表達(dá)式為???????????????? 。

下列關(guān)于樣品組成分析的說法,正確的是????????? (填標(biāo)號(hào))。

A.時(shí),樣品中一定不含雜質(zhì)

B.越大,樣品中含量一定越高

C.若步驟I中滴入KMnO4溶液不足,則測得樣品中Fe元素含量偏低

D.若所用KMnO4溶液實(shí)際濃度偏低,則測得樣品中Fe元素含量偏高


山東省2020年普通高中學(xué)業(yè)水平等級(jí)考試

化學(xué)試題參考答案

一、選擇題

1.D????????????? ????????????? 2.B????????????? ????????????? 3.C????????????? ????????????? 4.C????????????? ????????????? 5.C????????????? ????????????? 6.D????????????? ????????????? 7.A????????????? ????????????? 8.A????????????? ????????????? 9.B????????????? ????????????? 10.B

二、選擇題

11.BC????????????? 12.C????????????? ????????????? 13.D????????????? ????????????? 14.AD????????????? ????????????? 15.BC

三、非選擇題

16.(1)增大接觸面積,充分反應(yīng),提高反應(yīng)速率;

(2)過量的MnO2消耗了產(chǎn)生的Ba(OH)2

(3)蒸發(fā)

(4)H2O2;4.9

(5)

17.(1)正四面體形;分子晶體

(2)NH3、AsH3、PH3;AsH3、PH3、NH3;NH3、PH3、AsH3

(3)6;1

(4)4;(0.5,0,0.25)、(0.5,0.5,0);4

18.(1)+40.9

(2);

(3)乙;p1、p2、p3;T1時(shí)以反應(yīng)Ⅲ為主,反應(yīng)Ⅲ前后氣體分子數(shù)相等,壓強(qiáng)改變對(duì)平衡沒有影響

(4)A

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及時(shí)蒸出產(chǎn)物(或增大乙酸或乙醇的用量);

(2)取代反應(yīng);羰基、酰胺基

(3)CH3COCH2COOH;

(4)

20.(1)平衡氣壓,使?jié)恹}酸順利滴下; NaOH溶液;

(2)在裝置A、B之間加裝盛有飽和食鹽水的洗氣瓶

(3)酸式;C

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;B、D

 

 

 

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